![]() ![]() The cookie is used to store the user consent for the cookies in the category "Other. This cookie is set by GDPR Cookie Consent plugin. The cookies is used to store the user consent for the cookies in the category "Necessary". The cookie is set by GDPR cookie consent to record the user consent for the cookies in the category "Functional". The cookie is used to store the user consent for the cookies in the category "Analytics". These cookies ensure basic functionalities and security features of the website, anonymously. Necessary cookies are absolutely essential for the website to function properly. An additional aerodynamic force arises if the ball is spinning. Was this answer helpful? Why 45 degrees is the best angle of trajectory?Ī launch at 45 degrees would allow the ball to remain in the air for a longer time, but it would then be launched at a lower horizontal speed at the start and it would slow down more because of the longer flight time. Horizontal range depends upon angle of projection and it is same for complementary angles i.e. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees. The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity. Assuming that v2/g is constant, the greatest distance will be when sin(2θ) is at its maximum, which is when 2θ = 90 degrees. The equation for the distance traveled by a projectile being affected by gravity is sin(2θ)v2/g, where θ is the angle, v is the initial velocity and g is acceleration due to gravity. How do you calculate projectile distance? The range of a projectile for a given initial velocity is maximum when the angle of projection is 45∘.
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